Python: Passing a function name as an argument in a function -

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I am trying to pass the function name to another function in the form of argument, but I get an error : "TypeError: 'Str' object is not worth calling" Here is a simple example of the problem: 

  def doIt (a, func, y, z): result = z result = func Return dork1 (arg1, arg2, arg3): thing = (arg1 + arg2) / arg3 return talk def dork2 (arg1, arg2, arg3): object = arg1 + (arg2 / arg3) return Talk about

when I call this: 

  Var = 'dork1' ned = doIt (3, var, 4, 9) print (ned)

I am getting: 

  traceback ( Most recent call final): File "& lt; pyshell # 9", line 1, & lt; Module & gt; (A, Y, Result) Type: Error: 'str' is not worth the object corner

If you want to pass name to the function, as you said and you are doing, of course you can not call it - why a" Will call a name "? It's meaningless.

If you want to call it, then pass the function yourself, which is the most powerful no 

  var = 'dork1' / Code>  
 but without the quote  
  var = dork1  
 
 
 
  edit : O.P. in a comment How to obtain the miracle (!) Function object function name (in the form of a string) With this, it was shown to me that in a tutorial taught in OSCON (which I am just refunding) - get slides and pages 47 See, "Lazy-loading callback": 
 
  class LazyCallable (object): def __init __ (self, name): self.n, self.f = name, any def __call __ (Self, * a, ** k): if self.f none: modn, Funcn = self.n.rsplit ('.', 1) if not in modn sys.modules: __impo Rt___ (modn) self.f = getattr (sys.modules [modn], funcn) self.f (* a, * * k)  
 
 then you  is usable ('somemodule .dork1 ')  and can stay happily any time later. If you do not have to deal with the modules of the course (which is a strange architecture that should be meant! -) It is easy to adjust this code.

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