Order of operations question in Ruby -

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I am starting an example of a class that tests the similarities of two formulas.

The calculation value of the formula is actually the same: 

  RubyKeyem :: Chemical.N.NEW ("SOOS"). Fw = & gt; 96.0 RubyChem :: Chemical.new ("OSSO"). FW = 96.0

When I created a new square to test the similarities of these two instances, I was surprised at the results: 

  x = RubyKeym :: BalanceCam.New ("SOOS", "OSSO") x.balanced = & gt; False y = RubyKeym :: BalanceCam.New ("SOOS", "SOOS") Y.balanced = & gt; True

RubyKeym :: BalanceJam Initialisation method is here: 

  Def start (Formula 1, Formula 2) @balanced = RubyChem :: Chemical.Nn ( Formula1) .fw == RubyKeyem :: Chemical.N.N (Formula2) .fw &

Why not Ruby assumes FW for Formula 1 and Formula 2 and similarity of those values Checks? What is the order of operations in Ruby and what is Ruby doing? I can see that I lack the understanding of this issue. How can I make this work? Thank you in advance.

You probably do not want to see the floating point number of equality, instead you should compare the deltas .

Try it in irb: 

  x = 1.000001 y = 1.0 x == y (x-y) .bbs < 0.00001

Therefore, you find a delta like 0.00001 that you think floating point will handle any difference in arithmetic and use it in this way. You should never do == floats.


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