php - mysql get non existing results -

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Using php and mysql, I have a table "subdomain" that contains subdomains for my application, Based on a category. Subdomain-id, cat_id, subdomain

There are subdomains in some categories and others do not have it. Those who do not have a subdomain, I want to be a subdomain 'www'.

Now there are some values ​​in my subdomain table, for example: 

  Now, I have an array of cat_id, for example $ aCatIds = array (1, 1, 2, 2, 2) 5,6,8);  
 I want something like this at the end of the mysql query:  
  array (0 = & gt; (cat_id = "1", subdomain = "www"), 1 = & Gt; (cat_id = "5", subdomain = "www"), 2 = & gt; (cat_ id = "6", subdomain = "sale"), 3 =>  
 < P> Is it possible only with a mysql query? 
 
 I use php and tried things like this: 
 
  $ stmt = "sub - Select the cat_id, ifnull ('www', subdomain) in the form of subdomain from domains where in cat_id ("Implode (',', $ aCatIds).");  
 
 But only those values Which is set (6 in the example given above), and I do not know how to get mysql to expect the array.

To make this work, you must include the existing data (left) (where cat_id is present). For example, if I consider the cat table , Which is in the cat_id context, then it will: 

 select  c.id as Cat_id, IFNULL (s.subdomain, 'www') to cat C LEFT Join subdomain ON s.cat_id = c.id WHERE c.id IN (1,2,3) , 4);

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