##*/ use in UNIX Shell Scripting -

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Can anyone explain how ## * / UNIX shell works in scripting? I have seen that it uses corn Is in the shell. This is used specifically to remove the file extension.

For example, "Func_write_app_log" is being removed from the $ {CIE_STATUS_FILE ## * /} status file

Assume that the file is CIE_STATUS_FILE.DAT, then ## * / CIE_STATUS_FILE

This also works in Bash and is described as:

< P> $ {string ## substring}

$ removes the longest match of the substring from the front of the string.

is a wildcard which means Anything matches. Your example removes the path from the file, the extension No. 

 $ bazfile = '/ foo / bar / baz.txt' $ echo $ {bazfile ## * /} baz.txt

the extension you want to use To delete it, % :

$ {string% substring}

removes at least the $ string of the substring $ string Back. 

 $ echo $ {bazfile%. *} / Foo / bar / baz

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